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Variable Sized Arrays Discussions | C++ | HackerRank Variable Length Arrays in C and C++ - GeeksforGeeks

Variable Sized Arrays Variable Sized Arrays Discussions | C++ | HackerRank Consider an  -element array,  , where each index   in the array c...

Friday, April 2, 2021

1D Arrays in C step by step hackerrank solution C Solution For HackerRank Problem: 1D Arrays in C 1D Arrays in C | HackerRank

1D Arrays in C

1D Arrays in C step by step hackerrank solution  C Solution For HackerRank Problem: 1D Arrays in C      1D Arrays in C | HackerRank

 An array is a container object that holds a fixed number of values of a single type. 

To create an array in C, we can do int arr[n];. 

Here, arr, is a variable array which holds up to integers. 


The above array is a static array that has memory allocated at compile time. 

A dynamic array can be created in C, using the malloc function and the memory is allocated on the heap at runtime. 

To create an integer array, of size , int *arr = (int*)malloc(n * sizeof(int)) , where points to the base address of the array. 

In this challenge, you have to create an array of size dynamically, input the elements of the array, 

sum them and print the sum of the elements in a new line.

 Input Format The first line contains an integer, . 

The next line contains space-separated integers.

Output Format Print in a single line the sum of the integers in the array. 

Sample Input 0 

16 13 7 2 1 12

 Sample Output 0 

51 

Sample Input 1

 7 

1 13 15 20 12 13 2

 Sample Output 1

 76



 #include <stdio.h>

#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */
    int n, sum=0;
    scanf("%d",&n);
      
    int *arr=(int*)malloc(n*sizeof(int));
    for(int i=0;i<n;i++)
    {
        scanf("%d",&arr[i]);
    }
    for(int i=0;i<n;i++)
    {
        sum+=arr[i];
    }
    
    printf("%d",sum);
    return 0;
}












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